Termination w.r.t. Q of the following Term Rewriting System could be proven:

Q restricted rewrite system:
The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.


↳ QTRS
  ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.

Q DP problem:
The TRS P consists of the following rules:

IMPL2(x, y) -> XOR2(and2(x, y), xor2(x, T))
OR2(x, y) -> XOR2(x, y)
OR2(x, y) -> AND2(x, y)
IMPL2(x, y) -> AND2(x, y)
IMPL2(x, y) -> XOR2(x, T)
AND2(xor2(x, y), z) -> AND2(y, z)
AND2(xor2(x, y), z) -> AND2(x, z)
EQUIV2(x, y) -> XOR2(y, T)
OR2(x, y) -> XOR2(and2(x, y), xor2(x, y))
AND2(xor2(x, y), z) -> XOR2(and2(x, z), and2(y, z))
NEG1(x) -> XOR2(x, T)
EQUIV2(x, y) -> XOR2(x, xor2(y, T))

The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ DependencyPairsProof
    ↳ QDP
      ↳ DependencyGraphProof

Q DP problem:
The TRS P consists of the following rules:

IMPL2(x, y) -> XOR2(and2(x, y), xor2(x, T))
OR2(x, y) -> XOR2(x, y)
OR2(x, y) -> AND2(x, y)
IMPL2(x, y) -> AND2(x, y)
IMPL2(x, y) -> XOR2(x, T)
AND2(xor2(x, y), z) -> AND2(y, z)
AND2(xor2(x, y), z) -> AND2(x, z)
EQUIV2(x, y) -> XOR2(y, T)
OR2(x, y) -> XOR2(and2(x, y), xor2(x, y))
AND2(xor2(x, y), z) -> XOR2(and2(x, z), and2(y, z))
NEG1(x) -> XOR2(x, T)
EQUIV2(x, y) -> XOR2(x, xor2(y, T))

The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph contains 1 SCC with 10 less nodes.

↳ QTRS
  ↳ DependencyPairsProof
    ↳ QDP
      ↳ DependencyGraphProof
        ↳ QDP
          ↳ QDPAfsSolverProof

Q DP problem:
The TRS P consists of the following rules:

AND2(xor2(x, y), z) -> AND2(y, z)
AND2(xor2(x, y), z) -> AND2(x, z)

The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using an argument filtering and a montonic ordering, at least one Dependency Pair of this SCC can be strictly oriented.

AND2(xor2(x, y), z) -> AND2(y, z)
AND2(xor2(x, y), z) -> AND2(x, z)
Used argument filtering: AND2(x1, x2)  =  x1
xor2(x1, x2)  =  xor2(x1, x2)
Used ordering: Quasi Precedence: trivial 


↳ QTRS
  ↳ DependencyPairsProof
    ↳ QDP
      ↳ DependencyGraphProof
        ↳ QDP
          ↳ QDPAfsSolverProof
            ↳ QDP
              ↳ PisEmptyProof

Q DP problem:
P is empty.
The TRS R consists of the following rules:

xor2(x, F) -> x
xor2(x, neg1(x)) -> F
and2(x, T) -> x
and2(x, F) -> F
and2(x, x) -> x
and2(xor2(x, y), z) -> xor2(and2(x, z), and2(y, z))
xor2(x, x) -> F
impl2(x, y) -> xor2(and2(x, y), xor2(x, T))
or2(x, y) -> xor2(and2(x, y), xor2(x, y))
equiv2(x, y) -> xor2(x, xor2(y, T))
neg1(x) -> xor2(x, T)

Q is empty.
We have to consider all minimal (P,Q,R)-chains.
The TRS P is empty. Hence, there is no (P,Q,R) chain.